Math, asked by sanrajsingh6721, 1 year ago

Find the radius of a circle whose area is equal to the sum of areas of three circles with radii 8 cm, 9 cm, 12 cm respectively.

Answers

Answered by Panzer786
7
Hii friend,

RADIUS OF FIRST CIRCLE (R1) = 8 CM

RADIUS OF SECOND CIRCLE (R2) = 9 CM

RADIUS OF THIRD CIRCLE (R3) = 12 CM

THEREFORE,

AREA OF THE BIGGEST CIRCLE = π(R1)² + π(R2)² + π(R3)² = π[(R1)² + (R2)² + (R3)²

= 22/7 × [(8)² + (9)² + (12)²]

= 22/7 × [ 64 + 81 + 144]

= 22/7 × 289

= 22 × 47 = 1034 CM² .

HENCE,

THE AREA OF THE BIGGEST CIRCLE = 1034 CM².

HOPE IT WILL HELP YOU.... :-)
Answered by shawnsanthosh
0

Answer:

RADIUS OF FIRST CIRCLE (R1) = 8 CM

RADIUS OF SECOND CIRCLE (R2) = 9 CM

RADIUS OF THIRD CIRCLE (R3) = 12 CM

THEREFORE,

AREA OF THE BIGGEST CIRCLE = π(R1)² + π(R2)² + π(R3)² = π[(R1)² + (R2)² + (R3)²

= 22/7 × [(8)² + (9)² + (12)²]

= 22/7 × [ 64 + 81 + 144]

= 22/7 × 289

= 22 × 47 = 1034 CM² .

HENCE,

THE AREA OF THE BIGGEST CIRCLE = 1034 CM².

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