Find the radius of a circle whose circumference is equal to the sum of the circumferences of the two circles of diameters 36 cm and 20 cm.
Answers
Answered by
114
let radius of one circle [r1] =18 cm
radius of 2nd circle [r2] = 10 cm
radius of 3rd circle[r3] = ?
ATQ
C1 + C2 = C3
2лr1 +2лr2 =2лr3
2л (r1 + r2) = 2лr3
18 + 10 = 2лr3/2л
28 = r3
radius of 3rd circle is 28 cm.
radius of 2nd circle [r2] = 10 cm
radius of 3rd circle[r3] = ?
ATQ
C1 + C2 = C3
2лr1 +2лr2 =2лr3
2л (r1 + r2) = 2лr3
18 + 10 = 2лr3/2л
28 = r3
radius of 3rd circle is 28 cm.
Answered by
17
Answer:
Step-by-step explanation:
we know that
the circumference of circle = 2πr
where r is the radius
now.
the circumference of circle of radius 15 cm = 2π×15= 30π cm
&
the circumference of circle of radius 18cm = 2π×18 = 36π
According to question
the circumference of circle whose radius is r = 30π+36π = 66π
=> 2πr =66π
=> r = 33 answer
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