Question

Find the radius of a circle whose diameter has (-3,-4) (3,4) as its end points

Answer 1

solution:

Distance$=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

here,

$x_1=-3\\x_2=3\\y_1=-4\\y_2=4$

$Diameter =\sqrt{(3-(-3))^2+(4-(-4))^2} \\Diameter=\sqrt{(3+3)^2+(4+4)^2} \\Diameter=\sqrt{6^2+8^2}\\Diameter=\sqrt{(6+8)^2} \\Diameter=6+8\\Diameter=14$

$Radius=\frac{Diameter}{2}$

$Radius=\frac{14}{2}\\\\Radius=7$

∴The radius of the circle is 7