Question

Find the radius of curvature at (1/4, 1/4)
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Answer 1

Step-by-step explanation:

Given points ( 1/4, 1/4)

x= 1/4

y= 1/4

From the equation

${x}^{2} + {y}^{2} = {r}^{2} \\ ({ \frac{1}{4} }^{2} ) + ({ \frac{1}{4} }^{2} ) = {r}^{2} \\ r = \sqrt{ \frac{1}{16} + \frac{1}{16} } \\ r = \sqrt{ \frac{2}{16} } \: or \: \frac{ \sqrt{2} }{4}$

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