Find the radius of curvature for the curve x^3 + y^3 = 3axy on the point (3a/2, 3a/2)
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Answered by
10
according to question
x^3 + y^3 = 3axy
Thus at point (3a/2, 3a/2)
Putting the coordinates in the equation
27 a^3/8 + 27 a^3/8 = 54a^3/4
Thus
a = 1/2
Thus the coordinates are (1/2, 1/2)
x^3 + y^3 = 3axy
Thus at point (3a/2, 3a/2)
Putting the coordinates in the equation
27 a^3/8 + 27 a^3/8 = 54a^3/4
Thus
a = 1/2
Thus the coordinates are (1/2, 1/2)
Answered by
12
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