Question

find the radius of curvature of a plain convex lens whose focal length is 0.3 and mu= 1.5

Answer 1

Answer:

Explanation:

Her f=0.3Ωm=30cm,R1=∞( for plane surface ),R2=?,μ=1.5

On applying Lensmaker formula , we have

∴1f=(μ−1)(1R1−1R2)⇒130=(1.5−1)(1∞−1R2)

⇒130=0.5(−1R2)⇒R2=−0.5×30=−15cm

∴ Radius of curved surface =15 cm.