Find the Radius of curvature of the curve y= x3 at (1 1 )
Answers
Answered by
0
Answer:
Radius of curvature
=∣
y
′′
(1+y
′
)
2
3
∣
Now
y
′
∣
(1,2)
=
y
2x
∣
1,2
=1
And
y
′′
∣
1,2
=
y
2
2y−2xy
′
∣
1,2
=
y
2
2y−2x
y
2x
∣
1,2
=
y
3
2y
2
−4x
2
∣
1,2
=
8
8−4
=
2
1
.
Therefore
R=∣
2
1
(1+1)
2
3
∣
=
2
1
2
2
=4
2
Similar questions