Question

find the radius of given eaqution
$r^{2} = 3^{2} + 4^{2} =$
​

Answer 1

An equation of the circle with center (h,k) and radius r is

(x−h)

2

+(y−k)

2

=r

2

So, comparing (x−2)

2

+(y+5)

2

=13 that is (x−2)

2

+(y−(5))

2

=13 with the above equation of circle we get:

h=2, k=−5 and r=

13

Therefore, center of the circle is (2,−5) and radius of the circle is r=

13

.

Answer 2

Answer:

hope it is helpful

thanks