Question

find the radius of the 4th orbit of Be3+ ion​

Answer 1

this is answer

Explanation:

According to Bolois model of atom,

8= 0.529xn2 Å 7) Be=B4 zz = 0.529 x 3 / 505294 20-21 7

Answer 2

Answer:

The radius of the 4th orbit of the Be³⁺ ion is 2.116 A°.

Explanation:

The formula for the radius of hydrogen-like species is = 0.529×$\frac{n^{2} }{z}$ A°

Be³⁺has only one electron so it is a hydrogen-like species.

n is the principal quantum no of orbit

z is the atomic number

Given that,

              n = 4

              z = 4

The radius of orbit =  0.529×$\frac{16}{4}$ A° =  2.116 A°