Question

Find the radius of the base of a right circular cylinder whose curved surface area is
352sq.cm and height is 16cm.​

Answer 1

Step-by-step explanation:

Height of cylinder ( H ) = 16 cm

Curved Surface area of cylinder = 352

2πRH = 352

2 × 22/7 × R × 16 = 352

R = ( 352 × 7 ) / ( 2 × 22 × 16 )

R = 2464 / 704

R = 3.5 cm

Hence,

Radius of base of right circular cylinder = 3.5 cm.

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Radius\:of\:base=3.5\:cm}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{C.S.A\:of\:cylinder= 352 \: cm}^{2} \\ \\ : \implies \text{Height(h) = 16 \: cm} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{Radius\: of \: base= ? }$

• According to given question :

$\bold{As \: we \: know \: that} \\ : \implies \text{C.S.A\: of \: cylinder} =2\pi rh \\ \\ : \implies 352=2 \times \frac{ 22}{7} \times r\times 16 \\ \\ : \implies 2464=704 \times r \\ \\ \green{ : \implies\text{ r=3.5\:cm}}\\ \\ \bold{Formula\:related\:to\:the\:topic} \\ \circ\: \text{T.S.A\: of \: cylinder} =2\pi r(h + r)\\\\ \circ\: \text{Volume\: of \: cylinder} =\pi r^{2}h$