Question

Find the radius of the circle AB = AC, triangle BAC = 30 in the figure?​

Answer 1

The angle subtended by a chord at center is double the angle subtended by it on any other point on the major segment of circle.

So ∠BOC=60

∘

ΔBOC

OB=OC

The sides are equal and included angle is 60

∘

So the triangle is eqquilateral

Hence BC=OB(radius)

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Answer 2

Step-by-step explanation:

if boc=30 then boc must be double but this boc is half if it is outer angle