Question

Find the radius of the circle in which a central angle of 60° intercepts an arc of length 37.4 cm (use π = 22/7).

Answer 1

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let the radius of circle be "r"

central angle(¥) =60° = π/ 3 radiant

arc length (l) = 37.4

we know from formula...

central angle (¥) = arc length(l) ÷ radius

=). π/3 = 37.4 / r

=). r = 37.4 ×3 /π = 112.2 / π cm

=). r = 112.2 ×7/ 22 = 35.7 cm ans

Answer 2

let the radius of circle be "r"

let the radius of circle be "r"central angle(¥) =60° = π/ 3 radiant

let the radius of circle be "r"central angle(¥) =60° = π/ 3 radiantarc length (l) = 37.4

let the radius of circle be "r"central angle(¥) =60° = π/ 3 radiantarc length (l) = 37.4we know from formula...

let the radius of circle be "r"central angle(¥) =60° = π/ 3 radiantarc length (l) = 37.4we know from formula...central angle (¥) = arc length(l) ÷ radius

let the radius of circle be "r"central angle(¥) =60° = π/ 3 radiantarc length (l) = 37.4we know from formula...central angle (¥) = arc length(l) ÷ radius=). π/3 = 37.4 / r

let the radius of circle be "r"central angle(¥) =60° = π/ 3 radiantarc length (l) = 37.4we know from formula...central angle (¥) = arc length(l) ÷ radius=). π/3 = 37.4 / r=). r = 37.4 ×3 /π = 112.2 / π cm

let the radius of circle be "r"central angle(¥) =60° = π/ 3 radiantarc length (l) = 37.4we know from formula...central angle (¥) = arc length(l) ÷ radius=). π/3 = 37.4 / r=). r = 37.4 ×3 /π = 112.2 / π cm=). r = 112.2 ×7/ 22 = 35.7 cm ans