Question

Find the radius of the circle in which a central angle of 60° intercepts an arc of length 37.4 cm (given π =22/7).

Answer 1

area of arc = theta/3602πr
let x be the radius of the circle

$37.4 = (60 \div 360) \times 2 \times (22 \div 7) \times x$

therefore by solving
x = 71.4 cm

Answer 2

${\fbox{\huge{\tt{Solution\::}}}}$

Let "theta" be written as ¤

radius be "r"

r=?

l (length of arc) = 37.4 cm

=> 37.4 = (¤/180) πr

=> 37.4 = 60/180 * 22/7 * r

=> 37.4 * 3 * 7/22 = r

=> 35.7= r (ans.)