Find the radius of the circle inscribed in the triangle abc, having sides 10 cm, 10 cm and 16 cm.
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the area of the triangle = √s(s-a) (s-b) (s-c)
semi perimeter = 10+10+16/2
= 36/2
= 18
now, Area =√18(18-10)(18-10)(18-16)
=√18*8*8*2
=√2*3*3*2*4*2*4*2
=2*2*3*4
= 48cm^2
The radius of circle inscribed in triangle abc =48/18=2.68cm
semi perimeter = 10+10+16/2
= 36/2
= 18
now, Area =√18(18-10)(18-10)(18-16)
=√18*8*8*2
=√2*3*3*2*4*2*4*2
=2*2*3*4
= 48cm^2
The radius of circle inscribed in triangle abc =48/18=2.68cm
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