Find the radius of the circle passing through the points (0,0), (-2,1)and (-3,2)
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Step-by-step explanation:
Let P(x, y) be the centre of the circle passing through the points O(0, 0), A(-2, 1) and B(-3, 2). Then,
OP = AP = BP
Now, OP = AP OP2 = AP2
x2 + y2 = (x + 2)2 + (y - 1)2
x2 + y2 = x2 + y2 + 4x - 2y + 5
4x - 2y + 5 = 0 ...(i)
Now, OP = BP OP2 = BP2
x2 + y2 = (x + 3)2 + (y - 2)2
x2 + y2 = x2 + y2 + 6x - 4y + 13
6x - 4y + 13 = 0 ...(ii)
On solving equations (i) and (ii), we get x = 3/2 and y = 11/2
Thus, the coordinates of the centre are ( 3/2 , 11/2)
Now, radius = OP = √(x^2+y^2) =√9/4 + 121/4 =1/2 √130
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