Question

Find the radius of the circle whose center is [2,0]
and which passes through the point [7, -
12]

Answer 1

Answer:

0

Step-by-step explanation:

The centre of the circle is (2,0).

It touches the y axis. It can touch the y axis only at (0,0) and it's radius is 2 units.

So it's eqn.is (x-h)^2+(y-k)^2=1 where (h,k)=(2,0) and radius 2 units.

So eqn of the circle is (x-2)^2+(y-0)^2=4

ie x^2+y^2–4x=0