Question

find the radius of the circle whose centre is 3,2 and passes through the point -5,6​

Answer 1

Step-by-step explanation:

Given,

Centre of circle 3,2(o)

Another point - 5,6(a)

By using distance formula

OA²=(x1-x2)²+(y1-y2)²

OA²=[3-(-5)]²+(2-6)²

OA²=(3+5)²+(-4)²

OA²=(8)²+16

OA²=64+16

OA²=80

• Therefore, the radius of circle is under root 80

Answer 2

Step-by-step explanation:

given,

centre of circle P(3,2) and passes through the point Q(-5,6);

the distance between centre and the point(radius) =root((x2-x1)^2+(y2-y1)^2)

=root((-5-3)^2+(6-2)^2)

=root(80)=4root5

hope this helps you...