Question

Find the radius of the circle whose centre is (3,2) and passes through (-5,6)​

Answer 1

$\huge\star\underline\blue{Answer:-}$

Given

Centre of circle = (3,2)

Point on circle=(-5,6)

Distance b/w these points is equal to radius of circle.

$distance = \sqrt{ {{( - 5 - 3)}^{2} + ( 6 - 2) }^{2} } \\ = \sqrt{64 + 16} \\ 10 \: units$

Hence radius=10 units

$area \: of \: circle = \pi {r}^{2} \\ = \pi ({10}^{2} ) \\ = \pi \times 100 \\ = 3.14 \times 100 \\ = 314 \: sq.units$

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Answer 2

Answer:

√ 80 units

Step-by-step explanation:

Given :

Centre point ( 3 , 2 )

Passing point ( - 5 , 6 )

We have standard equation of circle :

( x - h )² + ( y - k )² = P²

Putting values here we get :

( - 5 - 3 )² + ( 6 - 2 )² = P²

( - 8 )² + ( 4 )² = P²

P² = 64 + 16

P = √ 80

Therefore , radius of circle is √ 80 units :