Question

find the radius of the circle whose centre is ( 3,2) and passes through ( -5,6) ​

Answer 1

Answer:

✓16×5=4✓5 units

scoring exilent marks in exams

Answer 2

Answer:

8.94 units

Step-by-step explanation:

we know that eq of a circle is

(x-h)^2 + (y- k)^2 = r^2

where (h,k) is the centre

so eq becomes (x-3)^2 + (y- 2 )^2 = r^2

circle is passing through the point (-5,6), so if we subsitutue those values in eq we get the radius.

(-5-3)^2+(6-2)^2=r^2

(-8)^2 + (4)^2 = r^2

64+16= r^2

r= sqrt(80)= 8.94