Question

find the radius of the circle whose centre is (a sin theta ,a cos theta ) passes through origin​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Given :  circle whose center is (a sin theta ,a cos theta ) passes through origin​

To Find : radius of the circle

Solution:

circle whose center is (a sinθ ,a cosθ )

Equation of Circle

(x - asinθ)² + ( y-acosθ)² = r²

r is the radius of circle

circle passes through origin​

Hence ( x , y ) = ( 0 , 0) will satisfy equation of circle

(0 - asinθ)² + ( 0-acosθ)² = r²

=> a²sin²θ + a²cos²θ  = r²

=> a²(sin²θ + cos²θ)  = r²

sin²θ + cos²θ = 1

=> a²(1)  = r²

=> a = r

Hence radius of circle is  a

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