Question

find the radius of the circle whose circumference is equal to the sum of the circumference of circles with radii 10 cm,12 cm,18 cm.​

Answer 1

Step-by-step explanation:

Let the radius of the circle = R cm

∴ 2πR = 2π × 10 + 2π × 12 + 2π × 18

On dividing each term by 2π, we get:

R = 10 + 12 + 18 = 40 cm

∴ Radius of the circle obtained = 40 cm

And, its diameter = 2 × Radius

= 2 × 40 cm = 80 cm

Answer 2

Let the radius of the circle = R cm

Let the radius of the circle = R cm∴ 2πR = 2π × 10 + 2π × 12 + 2π × 18

Let the radius of the circle = R cm∴ 2πR = 2π × 10 + 2π × 12 + 2π × 18On dividing each term by 2π, we get:

Let the radius of the circle = R cm∴ 2πR = 2π × 10 + 2π × 12 + 2π × 18On dividing each term by 2π, we get:R = 10 + 12 + 18 = 40 cm

Let the radius of the circle = R cm∴ 2πR = 2π × 10 + 2π × 12 + 2π × 18On dividing each term by 2π, we get:R = 10 + 12 + 18 = 40 cm∴ Radius of the circle obtained = 40 cm

Let the radius of the circle = R cm∴ 2πR = 2π × 10 + 2π × 12 + 2π × 18On dividing each term by 2π, we get:R = 10 + 12 + 18 = 40 cm∴ Radius of the circle obtained = 40 cmAnd, its diameter = 2 × Radius

Let the radius of the circle = R cm∴ 2πR = 2π × 10 + 2π × 12 + 2π × 18On dividing each term by 2π, we get:R = 10 + 12 + 18 = 40 cm∴ Radius of the circle obtained = 40 cmAnd, its diameter = 2 × Radius= 2 × 40 cm = 80 cm

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