Find the radius of the circle whose end points of diameter are (24,1)and(2,23)
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diameter= √(x2-x1)^2 + (y2-y1)^2
= √(2-24)^2 + (23-1)^2
=√(-22)^2+(22)^2
= √484+484
= √968
=22√2
=31.11
therefore, radius =31.11/2
=15.55
= √(2-24)^2 + (23-1)^2
=√(-22)^2+(22)^2
= √484+484
= √968
=22√2
=31.11
therefore, radius =31.11/2
=15.55
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