Find the radius of the motion of 2C of charge moving with speed of 4m/s in a magnetic
field of 0.1 Tesla. Mass of charged particle is 4 gram.
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Explanation:
Given Find the radius of the motion of 2 C of charge moving with speed of 4 m/s in a magnetic field of 0.1 Tesla. Mass of charged particle is 4 gram.
- We need to find the radius of motion.
- Given q = 2C
- So v = 4 m/s
- Mass m = 4 gm
- Magnetic field B = 0.1 T
- Now we have F = qv = mv^2 / R
- Or R = mv / qB
- Substituting the values we get
- R = 4 x 4 / 2 x 0.1
- R = 16/0.2
- R = 80 m
Reference link will be
https://brainly.in/question/11024987
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