Find the radius of the smaller circle if the bigger circle with centre 'O' has radius of 1cm.
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To Find :-
The radius of the smaller circle if the bigger circle with center 'O' has radius of 1 cm.
Construction :-
A line segment OP is drawn joining the centers of both the circles.
Solution :-
Let the radius of the bigger circle be R = 1 cm, and the radius of the smaller circle be r.
(Refer to the given attachment)
OD = OC = OR = R = 1 cm (radius of the bigger circle)
PA = PR = PB = r (radius of the smaller circle)
Now,
OR = OP + PR
⇒ R = OP + r
⇒ OP = R - r
Hence, P is the midpoint of OR.
∠OAP and ∠PBO are 90° and adjacent sides are of same length (i.e. r), so AOBP is a square.
OP is the diagonal of AOBP.
OP = √2 × side of the square
⇒ OP = √2 × r
⇒ OP + r = OR
⇒ √2r + r = 1
⇒ r(√2 + 1) = 1
⇒ r = 1 / (√2 + 1)
Taking √2 as 1.414
⇒ r = 1 / (1.414 + 1)
⇒ r = 1 / 2.414
⇒ r = 0.414
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Anonymous:
Awesome
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