find the range 5+3sinx+4cosx
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Hey there,
Range of equation a sin X +b cos X is given by=>√(a^2+b^2) to -√(a^2+b^2)
So,range of 3 sinx + 4 cos x= -5 to +5
Adding 5 we get
Range of 5 + 3 sin X+ 4cos X=5-5 to 5+5
i,.e 0to 10
Hope it helps
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