Find the range of 1/(1+ sqrt(x) )
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Answer:
(0,1]
Step-by-step explanation:
domain is x >= 0
1+√x is a positive term as x >= 0
as x increases, 1+√x increases , so 1/(1+√x) reduces to 0 ( but not equal to 0, so open interval is used)
for min. value of x i.e. x = 0, value of function will be 1
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