Question

Find the range of 1/under root x^2-9

Answer 1

Answer:

math](x^2-9)>0[/math]

[math]=> (x-3)(x+3)>0[/math]

[math]x ∈ (-inf,-3)∪(3,inf)[/math]

For Range, [math]x ∈ (0,inf) [/math]

As for the selected values of domain, its corresponding value for the function will be +ve real numbers.

Hope it helps! :)

Answer 2

Answer:

1/√x^2-9

=1/(x-3)(x+3)

hope it helps.