Find the range of f(x)= 1 + 3cos 2x
Answers
Answered by
12
y=1+3cos2x
cos2x=y-1/3
x=arccos(y-1/3) /2
hence range is [-2,4]
cos2x=y-1/3
x=arccos(y-1/3) /2
hence range is [-2,4]
Similar questions