find the range of f(x)=3/x^2+x^-2+3
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Answer:
range=(3,∞)
Step-by-step explanation:
let 3/x² + 1/x² +3=y
now, (3+1+3x²)=yx²
4+3x²=yx²
yx²-3x²-4=0
x²(y-3)-4=0
x²=4/(y-3)
since x²≥0,
so, 4/(y-3)≥0
and y-3>0
y >3
range=(3,∞)
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