Find the range of f(x)= (x-3)/(3-x)
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the range is (-1,1)
f(x)=x−3∣x−3∣
x−3=0 (Denominator cannot be zero)
⇒x=3
∴ Domain: R−{3}
f(x)=⎩⎪⎪⎨⎪⎪⎧(x−3)(x−3)=1;−x−3(x−3)=1;x>3x<3
∴f(x)={1;−1;x>3x<3
∴Range ={−1,1}.
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