Math, asked by Anonymous, 9 months ago

find the range of first n natural numbers​

Answers

Answered by mysticaldimples59
9

Solution : Range of the first 'n' natural numbers = n - 1. Range of the last n negative integers = -1-(-n)=n-1. Range of the first 'n' positive even integers = 2n - 2 .

Answered by pulakmath007
1

The range of first n natural numbers is n - 1

Given : First n natural numbers

To find : The range

Solution :

Step 1 of 2 :

Write down first n natural numbers

First n natural numbers are 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 , . . . , n

Step 2 of 2 :

Find the range

We know that for a given set of observations range is defined as the difference between highest value and lowest value in the observations

Hence the required range

= Highest value - Lowest value

= n - 1

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