Question

find the range of quadratic function g(x)if g(x)=-2x^2+ 4x +10

Answer 1

Answer:

Step-by-step explanation:

Given function is

$\tt{g(x)=-2x^2+4x+10}$

Since 1st term of the quadratic equation is negative, so, its range will be

$\sf{\bigg(-\infty,\dfrac{-D}{4a}\bigg]}$

So,

$\sf{D=(4)^2-4\cdot(-2)\cdot10=16+80=96}$

$\sf{\therefore\,Range\,\,of\,\,g(x)\,\in\bigg(-\infty,\dfrac{-96}{-8}\bigg]}$

$\sf{\therefore\,Range\,\,of\,\,g(x)\,\in(-\infty,12\,]}$