Math, asked by nidhirajvarma, 5 months ago

Find the range of relation R given by R = [ {x,y}:y = x+6/x, where X, Y€N and x<6​

Answers

Answered by mathdude500
1
As x is less than 6, so Possible values of x are 1, 2, 3.
So when x = 1, y = 7
When x = 2, y = 5
When x = 3, y = 5

So range is {5, 7}
Answered by suman8615
0

Answer:

this is correct.........................

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