Question

find the range of the ball when is projected with a velocity of 29.4 metre per second at a height of 4.9 metre​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step by step

Step-by-step explanation:

R= U cosQ ×t

cosQ ×t U Cos Q =29.4

cosQ ×t U Cos Q =29.4 h=4.9

cosQ ×t U Cos Q =29.4 h=4.9t= √2h/g

cosQ ×t U Cos Q =29.4 h=4.9t= √2h/g=√2×4.9/√9.8

cosQ ×t U Cos Q =29.4 h=4.9t= √2h/g=√2×4.9/√9.8= √1

cosQ ×t U Cos Q =29.4 h=4.9t= √2h/g=√2×4.9/√9.8= √1.°. R=29.4×1

cosQ ×t U Cos Q =29.4 h=4.9t= √2h/g=√2×4.9/√9.8= √1.°. R=29.4×1= 29.4 ❤Ans❤

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