Math, asked by aaron1085, 9 months ago

Find the range of the following function​

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Answered by Anonymous
17

\huge{\boxed{\red{\star\;Answer}}}

\large{\boxed{\blue{\star\;Note}}}

  • Here I represented less than or equal with symbol as lessthan and greater than or equal symbol with greater than

\large{\underline{\pink{\star\; Solution}}}

  • -5<x<3
  • squaring
  • 0<x²<25
  • multiplying with 2
  • 0<2x²<50
  • multiplying with a negative sign
  • 0>-2x²>-50
  • adding 9
  • 9>f(x)>-41

Therefore range of f(x) is [-41,9]

Hope it helps ✔️✔️✔️

#Jai hindh

Answered by Anonymous
1

Answer:

[-41,9]

Step-by-step explanation:

Given inequality:

-5≤x≤3

or, 0≤x²≤25. [on squaring]

or, 0≥-2x²≥-50. [multiplying in. equ by -2]

or, 9≥9-2x²≥-41. [adding 9 to the in.equ]

or, -41≤f(x)≤9

so,the range is [-41,9]....

see the attachment for graphical approach!!!!

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