Question

find the range of the following function f(x)=2+5 sin 3x​

Answer 1

✨✨✨✨Answer:✨✨✨

let f(X)=y

$- 1 \leqslant \: \sin(3x) \leqslant \: 1 \: \\ - 1 \leqslant \frac{y - 2}{5} \leqslant \: 1 \\ - 5 \leqslant y - 2 \leqslant 5 \\ - 3 \leqslant y \leqslant 7$

now as

$y = 2 + 5 \sin(3x) > 0 \: \: coz \: \: \\ - 1 \leqslant \sin(3x) \leqslant 1$

the range is

{f(X):€R and

$- 3 \leqslant y \leqslant 7$

Answer 2

Answer:

Step-by-step explanation: