Question

find the range of the following function given by f( x) =1/ 2-sin 3x​

Answer 1

Step-by-step explanation:

-1≤sin thetha≤1

-1≤sin3x≤1

Multiply minus on both sides

Equality sign changes to ≥

-(-1≤sin3x≤1)

1≥-sin3x≥-1

Add 2 on both sides

2+1≥2-sin3x≥2+(-1)

3≥2-sin3x≥1

Inverse the inequality sign changes

1/3≤1/2-sin3x≤1

Range is (1/3,1)