Question

find the range of the function F(x)=1/2+sin3x​

Answer 1

FOR RANGE :

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now multiplying by -1 we get,

=> 1 ≥ - sin3x ≥ -1

adding 2 we get,

=> 2+1 ≥ 2 - sin3x ≥ 2-1

=> 3 ≥ 2-sin3x ≥ 1

now taking inverse we get,

so Range € [ ⅓ , 1 ]

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