Math, asked by IRUNMAN, 1 month ago

Find the range of the function g(x) = x^2+2x+1/x ​

Answers

Answered by husainy939
0

The given function is, f(x)=

x

2

−8x+12

x

2

+2x+1

⇒f(x)=

(x−6)(x−2)

x

2

+2x+1

It can be seen that function f is defined for all real numbers except at x=6 and x=2

Hence the domain of f is R−{2,6

Answered by UltimateAK
1

Answer:

  • for domain...
  • x-2 is not equal to zero. so x is not equal to 2. domain is R-{2} its range is {1,-1}. because it will give only 1 or -1 for any x belongs to R-{2}. we have function x-2/lx-21 . we know that Ix-21=+-(x-2) according to values of x.
  • so (x-2)/+-(x-2) =+-1

Step-by-step explanation:

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