Find the range of the function. Kindly show steps
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Answer:
x4 – 14x2 + 24x – k = 0 has four real and unequal roots .
Step-by-step explanation:
Let f(x) = x4 – 14x2 + 24x – k Then f'(x) = 4x3 – 28x + 24 = 4(x3 – 7x + 6) = 4(x – 1)(x – 2)(x + 3) So, f(x) = 0 has four unequal roots.
Now, f(– 3) = –117 – k,
f (1) = 11 – k and f(2) = 8 – k
By the sign scheme, f(1) < 0,
f(2) > 0 & f(– 3) < 0 ⇒ (8 – k) < 0,
11 – k > 0 & – 117 – k < 0 ⇒ k > 8,
k < 11 and k > – 117 ⇒ 8 < k < 11 Therfore, 8 < k
I hope it's helpful
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