Question

Find the range of values of k if kx^2 + 8x > 6 - k for all real values of x.​

Answer 1

Answer:

b2−4ac=(8)2−4(−2)(17−k)64−4(−2)(17−k)64+136−8k200>0>0>0>8k

so my answer is

k<200/8

Step-by-step explanation:

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