Question

Find the range of values of p for which 4 – p 2 > 2 p + 1.

Answer 1

ANSWER :

Given the equation x2+y2−2px−4py+3p+2=0 represents a circle, determine a range of values for p.

I don't think I can use the discriminant because there are y values so I can use:

g2+f2−c>0

g = -p

f = -2p

c = 3p + 2

(−p)2+(−2p)2−3p+2>0

=> p2+4p2−3p+2>0

=> 5p2−3p+2>0

I thought I would then find values for p and display them like p1<p<p2

I was going to use the quadratic formula:

=> 3±(−3)2−4(5)(2)√5

But the discriminant is a negative number so I don't think I am on the right path.

Please make me brainly