Question

find the range of y = sin(2sinx)​

Answer 1

$y=\sin (2 x) </p><p> y is defined \forall x \in \mathbb{R} \: \therefore the domain of y is (-\infty,+$

$Let \theta=2 x </p><p> y=\sin \theta \rightarrow-1 \leq y \leq+1 \forall \theta \in$

$Hence, y=\sin (2 x) \rightarrow-1 \leq y \leq+1 \forall \theta \in$

$\therefore the range of y is [-1,+1] </p><p>We can observe the domain and range of y from the graph of \# y=\sin \therefore the range of y is [-1,+1] </p><p>We \: can \: observe \: the \: domain \: and \: range \: of \: y \: from \: the \: graph \: of \# y=\sin$

$\operatorname{graph}\{\sin (2 x)[-6.25,6.234,-3.12,3.124]\}$