CBSE BOARD XII, asked by kartikdt, 5 months ago

find the range of y= (x-1) (x-2) /(x-3) (x-4) ​

Answers

Answered by HarishmaMathevan
0

Answer:

(x-1) (x-2) /(x-3) (x-4) =(x-1) (x-2) /(x-3) (x-2²)

=(x-1) (x-2) /(x-3)(x-2)

=( x-1) /(x-3)(x+2)

=(x-1) /(x²-x-6)

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