Question

find the range value of x for which 7+2x>0 and 5-3x>0​

Answer 1

Answer:

Range is only 1.

Step-by-step explanation:

Trial and error method.

5-3×-1=9

5-3×-2=11

5-3×-3=14 it goes on

5-3×1=2 so the range ends at 1 and starts at negative infinite.

5-3×2=-1 cause -1 is not grater than 0

Next,

7+2×1=10

7+2×2=11 it goes on.

7+2×-1=5

7+2×-2=3

7+2×-3=1

7+2×-4=-1 here it ends so for this it starts at -3 and ends at infinite.

Now,

The range of first is -∞ to 1

The range of second is -3 to ∞

So the range is from -3 to 1