find the rate at which a sum of money will double itself in 2 years, if the interest is compounded annually.
please help me I want full explanation.
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Answer:
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Step-by-step explanation:
ANSWER
If an amount 'P' is invested at an interest of r% p.a. for n years then the amount received after 'n' years is given by
⇒A=P(1+
100
r
)
n
here, let say the principal be Rs. P then amount is given to be Rs. 2P and n=2 years.
∴2p=p(1+
100
r
)
2
⇒2=(1+
100
r
)
2
⇒1+
100
r
=
2
⇒
100
r
=1.414−1 (∵
2
≅1.41.)
⇒
100
r
=0.414
⇒r=41.4%
Hence, the answer is 41.4%.
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