Find the rate at which a sum of money will double itself in 3 years, if the interest is
compounded annually.
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Let the Principal be 1
So, Amount is double, amount is 2
Time is 3 yrs
ATQ
A = P(1+r/100)^n
now put values in the formula..
2 = 1(1+r/100)^3
√2 = 1 (1+r/100).........cuberoot of 2
1.26 = 1 + r /100......... multiply 1 to bracket .
1.26 - 1 = r/100
0.26 = r /100
0.26 × 100 = r
26 = r
hence, the rate of interest is 26%.
Hope it helps you.
mark brainiest .
So, Amount is double, amount is 2
Time is 3 yrs
ATQ
A = P(1+r/100)^n
now put values in the formula..
2 = 1(1+r/100)^3
√2 = 1 (1+r/100).........cuberoot of 2
1.26 = 1 + r /100......... multiply 1 to bracket .
1.26 - 1 = r/100
0.26 = r /100
0.26 × 100 = r
26 = r
hence, the rate of interest is 26%.
Hope it helps you.
mark brainiest .
mukul9228:
Thanks for you help
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