Find the rate at which sums of money will double itself in 2 years if the
interest is compounded annually?
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Answer:
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Step-by-step explanation:
Answer:
41.4214% ( approx )
Step-by-step explanation:
Let the amount of money = x
Time = 2 years,
Let r be the annual rate of interest,
Thus, the amount of money after 2 years,
A=x(1+r)^2A=x(1+r)
2
According to the question,
x(1+r)^2=2xx(1+r)
2
=2x
(1+r)^2=2(1+r)
2
=2
(1+r)=\sqrt{2}\implies r = \sqrt{2}-1=1.41421356237-1=0.41421356237\approx 0.414214=41.4214\%(1+r)=
2
⟹r=
2
−1=1.41421356237−1=0.41421356237≈0.414214=41.4214%
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