Question

Find the rate constant for the given reaction A+B arrow product whose initial concentration of the reaction A and B are 'a"​

Answer 1

The given reaction is A+B⟶ Product

Let us suppose the rate law of this reaction is:-

Rate=K[A]a[B]b

where K is a rate constant.

a and b are order of the reaction with respect to the reactants A and B respectively.

Given that,

When [A] is doubled, the rate of the reaction is also doubled, so the reaction is first order w.r.t.A and hence a=1

When [A],[B] is doubled, the rate of reaction becomes 8 times. Now,

(Rate)new=K[2A]1[2B]b          −(ii)

Rate=K[A]1[B]b          −(iii)

Now, ∵ New rate of reaction is 8 times, so dividing (ii) by (iii) :-

⇒8=2.2b

23=21+b

Equating the exponents:-

⇒3=1+b⇒b=2

So, order of reaction w.r.t to B is 2

So, Rate=K[A][B]2

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