find the rate of change of the area of a circular disc with respect to its circumference when the radius is 3 cm
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Answered by
8
The area of a circle is
A = *r^2
Take the derivative with respect to time
dA/dt = 2**r*dr/dt
Substitute the appropriate values
dA/dt = 2**2*3 = 12 /sec
A = *r^2
Take the derivative with respect to time
dA/dt = 2**r*dr/dt
Substitute the appropriate values
dA/dt = 2**2*3 = 12 /sec
Answered by
2
circumference of circle
C = 2*pi*r
dC/dt = 2*pi*dr/dt = k
area of circle
A = 2*pi*r²
dA/dt = 2*pi*2rdr/dt
dA/dt = 2*3*k = 6k
C = 2*pi*r
dC/dt = 2*pi*dr/dt = k
area of circle
A = 2*pi*r²
dA/dt = 2*pi*2rdr/dt
dA/dt = 2*3*k = 6k
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